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Faraday's laws of electrolysis: mass deposited = (M × I × t) / (n × F), where M is molar mass, I current, t time, n electrons.
Guide étape par étape
- 1Input current, time, substance, electrons transferred
- 2Calculate moles and mass of product
- 3Determine Faraday efficiency
Exemples résolus
Entrée
Electroplate Cu: 1 A × 3600 s = 1.19 g Cu deposited (96,485 C/mol, 2 e⁻)
Résultat
Efficiency typically 85-95%
Erreurs courantes à éviter
- ✕Using wrong number of electrons per atom
- ✕Not accounting for overpotential
Questions fréquentes
Why is current efficiency < 100%?
Side reactions (water splitting, hydrogen evolution) compete with desired reaction.
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