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Euler column buckling predicts critical load at which slender columns fail by instability rather than material crushing. It's essential for structural safety.
ସୂତ୍ର
Calculate: P_cr = π²EI/(KL)² where K is effective length factor
- KL
- KL value — Variable used in the calculation
- K
- K value — Variable used in the calculation
ଷ୍ଟେପ୍-ଷ୍ଟେପ୍ ଗାଇଡ୍ |
- 1Calculate: P_cr = π²EI/(KL)² where K is effective length factor
- 2Compare to axial compression strength
- 3Results determine column design adequacy
ସମାଧାନ ହୋଇଥିବା ଉଦାହରଣ
ଇନପୁଟ୍
E = 200 GPa, I = 2×10⁹ mm⁴, L = 4 m, K = 1 (pinned)
ଫଳ
P_cr ≈ 2.47 MN (critical load)
Higher leads to buckling
ଏଡ଼ାଇବା ଯୋଗ୍ୟ ସାଧାରଣ ଭୁଲ
- ✕Using unsupported length instead of effective length
- ✕Neglecting lateral bracing effects on K
ବାରମ୍ବାର ଜିଜ୍ଞାସା
Why do long columns fail at lower loads?
Buckling instability dominates; longer unsupported length reduces critical load dramatically (proportional to 1/L²).
What is effective length factor K?
K accounts for end conditions: K=0.5 (fixed-fixed), K=1 (pinned-pinned), K=2 (cantilever).
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