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The period of a simple pendulum is the time for one complete oscillation (forward and back). For small angles, T = 2π√(L/g), where L is length and g is gravitational acceleration. Remarkably, period does not depend on the mass of the bob.

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  1. 1Period T = 2π × √(L / g)
  2. 2L = length of pendulum in metres
  3. 3g = 9.81 m/s² (Earth surface)
  4. 4Frequency f = 1 / T oscillations per second

ସମାଧାନ ହୋଇଥିବା ଉଦାହରଣ

ଇନପୁଟ୍
Pendulum length 1m on Earth
ଫଳ
T = 2.006 seconds
2π × √(1/9.81) = 2.006s

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