learn.howToCalculate
learn.whatIsHeading
Permutations with replacement count ordered arrangements where items can be repeated. Formula: n^k (n choices, k selections). Used in PIN codes, passwords, combination locks, and license plates.
Przewodnik krok po kroku
- 1Order matters AND repetition allowed
- 2Total = n^k (n choices for each of k positions)
- 3Example: 4-digit PIN with digits 0-9: 10^4 = 10,000 possible PINs
- 4Contrast: permutations without replacement = n!/(n-k)!
Rozwiązane przykłady
Wejście
3-letter code from 26 letters, repeats allowed
Wynik
26³ = 17,576 codes
Wejście
4-digit PIN (0–9)
Wynik
10⁴ = 10,000 PINs
Without replacement: 10×9×8×7 = 5,040
Gotowy do obliczeń? Wypróbuj darmowy kalkulator Permutations with Replacement
Spróbuj sam →