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Quadratic Formula

Solve ax² + bx + c = 0 equations

Quadratic Formula — ax² + bx + c = 0

x = (−b ± √(b²−4ac)) / 2a

Variable Key

a= coefficient of x²b= coefficient of xc= constantΔ= discriminant = b² − 4ac

Quadratic formula

Finds both roots simultaneously.

Discriminant analysis

Determines the nature of roots before solving.

Δ > 0
Δ = 0
Δ < 0

Vieta's formulas

Relationships between roots and coefficients.

Sum of roots
Product of roots

Vertex form

Rewrite in vertex form to find the parabola's turning point.

Vertex

The quadratic formula solves any equation of the form ax² + bx + c = 0 for x. It works for all quadratics — even ones that cannot be factored — making it the most universal solving method. The formula was known to Babylonian mathematicians as early as 2000 BC.

  1. 1Arrange the equation in standard form: ax² + bx + c = 0
  2. 2Identify a (coefficient of x²), b (coefficient of x), c (constant)
  3. 3Calculate the discriminant: Δ = b² − 4ac
  4. 4If Δ ≥ 0: substitute into x = (−b ± √Δ) / 2a for two real roots
  5. 5If Δ < 0: the equation has two complex (non-real) roots
x² − 5x + 6 = 0=x = 3 or x = 2Δ = 25−24 = 1 > 0. Roots: (5±1)/2
x² − 2x + 1 = 0=x = 1 (repeated)Δ = 4−4 = 0. One repeated root.
x² + x + 1 = 0=Complex rootsΔ = 1−4 = −3 < 0. No real solutions.
2x² + 3x − 2 = 0=x = 0.5 or x = −2Δ = 9+16 = 25. Roots: (−3±5)/4

When a = 0

The equation becomes linear (bx + c = 0), not quadratic. Solve as x = −c/b.

Vertex of the parabola

The x-coordinate of the vertex is x = −b/(2a), the midpoint of the two roots.

Δ valueNumber of real rootsGraph crosses x-axis
Δ > 0Two distinct real rootsAt two points
Δ = 0One repeated real rootTouches at one point
Δ < 0No real roots (complex)Does not cross

Fun Fact

The quadratic formula was first written in modern algebraic notation by René Descartes in 1637. Before that, mathematicians described the same method in words and geometric diagrams.

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